Most often, bimetallic radiators owners are purchased to replace cast-iron batteries, which for one reason or another failed or began to heat the room badly. To make this model of radiators well coped with its task, it is necessary to familiarize yourself with the rules for calculating the number of sections on the entire room.
The right decision itself will be the appeal to experienced specialists. Professionals can calculate the amount of bimetallic heating radiators quite accurately and efficiently. This calculation will help determine how many sections will be needed not only for one room, but also for the entire room, as well as for any type of object.
All professionals take into account the following data for counting the number of batteries:
All this data allow you to make calculation most accurate to install bimetallic batteries.
To make the calculation correctly, it is necessary for the beginning to calculate which heat losses will be, and then calculate their coefficient. For accurate data you need to consider one unknown, that is, walls. This applies primarily by corner rooms. For example, indoors are presented the following parameters: Height - two and a half meters, width - three meters, length - six meters.
The calculation is carried out in meters. According to these calculations, the wall area will be equal to seven and a half square meters. After that, it is necessary to calculate the heat loss in the formula p \u003d f * k.
Also multiplied by the temperature difference in the room and on the street, where:
For the correct calculation you need to take into account the temperature. If the temperature on the street is about twenty-one degrees, and in the room eighteen degrees, it is necessary to add two more degrees to calculate this room. To the resulting digit you need to add p windows and r doors. The result obtained should be divided into a number denoting the thermal power of one section. As a result of simple computing and it turns out to know how many batteries are necessary for heating the same room.
However, all these calculations are correct exclusively for rooms that have medium insulation indicators. As you know, the same premises do not happen, so it is necessary to take into account the correction coefficients to accurately calculate. They must be multiplied by the result obtained by calculating the formula. The coefficient corrections for the angular rooms are 1.3, and for premises located in very cold places - 1.6, for attic - 1.5.
To determine the power of one radiator, it is necessary to calculate how much the kilowatt heat will be needed from installed system Heating. The power that is needed to enjoy each square meter is 100 watts. The resulting number is multiplied by the number of square meters of the room. Then the figure is divided into the power of each individual section of the modern radiator. Some batteries consist of two sections and more. Making the calculation, you need to choose a radiator, which has an approximate number of sections. But still, it should be a little more calculated.
This is done in order to make the room warmer and not flaw on cold days.
Manufacturers of bimetallic radiators indicate their power for some data of the heating system.Therefore, buying any model, it is necessary to take into account the thermal pressure, which characterizes how the heat carrier is heated, and also how it heats the heating system. In technical documentation, the power of one section is often indicated for heat pressure in sixty-degrees. This corresponds to the water temperature in the radiator in ninety degrees. In those houses, where the premises are heated with cast-iron batteries, it is justified, but for new buildings, where everything is done modern, the water temperature in the radiator may well be lower. Heat pressure in such heating systems can be up to fifty degrees.
The calculation here is also not difficult. It is necessary to divide the radiator power to the figure denoting the thermal pressure. The number is divided into the figure specified in the documents. In this case, the effective power of the batteries will be slightly smaller.
It is necessary to put it in all formulas.
To deduct the desired number of sections in the radiator installed, not one formula can be used, but several. Therefore, it is worth assessing all the options and choose the one that is suitable for more accurate data. To do this, you need to know that on the standards of SNiP for 1 m², one bimetallic section may heat one meter and eighty centimeters of the area. To calculate how the number of sections are needed on 16 m², you need to divide this figure by 1.8 square meters. As a result, it turns out nine sections. However, this method is quite primitive and for more accurate definition it is necessary to take into account all of the above data.
There is another simple method for self-calculation.For example, if you take a small room in 12 m², then very strong batteries here. You can take, for example, the heat transfer is only one section in two hundred watts. Then, by the formula, you can easily calculate their quantity required for the selected room. To get the desired digit, you need 12 - this is the number of squares, multiply by 100, power per square meter and divide by 200 watts. This, as can be understood, is the value of heat transfer to one section. As a result of the calculations, the number six, that is, it is so many sections will need for the heating of the room in twelve squares.
You can consider another option for an apartment with a quadrature in 20 m².Suppose that the power of the bought radiator section is one hundred eighty watts. Then, substituting all the existing values \u200b\u200bin the formula, it turns out this result: 20 must be multiplied by 100 and divided by 180 will be equal to 11, which means that this number of sections will be needed for heating of this room. However, such results will really correspond to the premises where the ceilings are not above three meters, and the climatic conditions are not very tough. And the windows were not taken into account, that is, their number, therefore, a few more sections should be added to the end result, their number will depend on the number of windows. That is, you can install two radiator in which six sections will be installed. At the same time, another section was added to the windows and doors.
To make a calculation more accurate, you need to make a calculation by volume, that is, take into account three dimensions in the selected heated room. All calculations are done almost the same, only the capacity is the capacity calculated for one cubic meter, which are equal to forty one watt. You can try to calculate the number of sections of the bimetallic battery for the room with such an area, as in the embodiment above and compare the results. In this case, the ceilings height will be equal to two meters of seventy centimeters, and the square of the room will be twelve square meters. Then you need to multiply three to four, and then two and seven.
The result will be like this: thirty-two and four meters of cubic. It must be multiplied by forty one and it will turn out a thousand three hundred twenty-eight and four watts. Such radiator power will be perfect for heating this room. Then this result must be divided into two hundred, that is, the number of watts. The result will be equal to six hundred and sixty four hundredth, which means it will take a radiator for seven sections. As can be seen, the result of the calculation is much more accurate. In the end, it will not be necessary to even take into account the number of windows and doors.
You can also compare the results of calculating indoor with twenty square meters.To do this, multiply twenty-two and seven, it will turn out fifty-four cubic meters - this is the size of the room. Next, you need to multiply at forty-one and the result will be two thousand four hundred fourteen watts. If the battery will have a power in two hundred watts, then this figure needs to be divided into the result. As a result, twelve and seven will be released, and therefore for this room it is necessary for such a number of sections as in the previous calculation, but this option is much more accurate.
One of the most important issues of creating comfortable living conditions in a house or apartment is a reliable, correctly calculated and mounted, well-balanced heating system. That is why the creation of such a system is the main task in organizing the construction of your own home or during overhaul In the apartment high-rise buildings.
Despite the modern diversity of heating systems different types, Polarity leader still remains a proven scheme: the contours of the pipes with circulating coolant circulating on them, and heat exchange devices are radiators installed in the premises. It would seem - everything is simple, the batteries are under the windows and ensure the rebuable heating ... however, it is necessary to know that the heat transfer from radiators should correspond to the area of \u200b\u200bthe room, and a number of other specific criteria. Heat engineering calculations Funded on the requirements of SNiP is a rather complicated procedure performed by specialists. However, it is possible to perform it and on their own, naturally, with a permissible simplification. In this publication, it will be described how to independently carry out the calculation of heating batteries on the area of \u200b\u200bheated premises, taking into account various nuances.
But, first, you need to read the existing radiators of heating - from their parameters, the results of the calculations carried out are largely dependent.
This type of radiators did not discharged a special popularity, despite the fact that some models are given very elegant designer decoration. The problem is that the shortcomings of such heat exchange devices significantly exceed their advantages - a low price of a relatively small mass and ease of installation.
Thin steel walls of such radiators are not enough heat - quickly heated, but also as rapidly cooled. Problems may occur during hydraulic blows - welded sheets of sheets sometimes give to leak. In addition, inexpensive models that do not have a special coating are subject to corrosion, and the service life of such batteries is small - usually manufacturers give them a rather small duration of operation of the warranty.
In the overwhelming majority steel radiators represent a one-piece design, and variation of heat transfer by changing the number of sections does not allow. They have a passport thermal power, which immediately need to choose, based on the area and features of the room, where they are planned to be installed. Exception - some tubular radiators have the ability to change the number of sections, but this is usually done under the order, in the manufacture, and not at home.
Representatives of this type of batteries are probably familiar to everyone from early childhood - it was such a harmonica who were previously established everywhere.
Perhaps such batteries of MS -140- 500 and did not differ in particular grace, but it was right that there were not one generation of residents. Each section of such a radiator provided heat transfer in 160 W. Radiator team, and the number of sections, in principle, was not limited to anything.
Currently, a lot of modern cast iron radiators are on sale. They are already distinguished by more elegant appearance, smooth smooth outer surfaces that facilitate cleaning. Exclusive options are available, with an interesting embossed pattern of ironing to pour.
With all this, such models fully retain the main advantages of cast-iron batteries:
If you do not take into account the external data of old cast-iron batteries, then the disadvantages can be noted the fragility of the metal (accented strikes are unacceptable), the relative complexity of the installation associated to more extent with the massiveness. In addition, not any wall partitions will be able to withstand the weight of such radiators.
Aluminum radiators, appearing relatively recently, very quickly won popularity. They are relatively inexpensive, have a modern, fairly elegant appearance, possess excellent heat transfer.
High-quality aluminum batteries are able to withstand pressure in 15 and more atmospheres, the high temperature of the coolant is about 100 degrees. At the same time, the thermal return from one section in some models sometimes reaches 200 W. But at the same time, they are a small mass (weight of the section - usually up to 2 kg) and do not require a large amount of coolant (capacity - no more than 500 ml).
Aluminum radiators are available on sale as a set of batteries, with the ability to change the number of sections and solid products designed for certain power.
Disadvantages of aluminum radiators:
Made of all aluminum batteries are the highest quality - manufactured using anodic oxidation of metal. These products are practically not terrible oxygen corrosion.
Externally, all aluminum radiators are roughly similar, so it is necessary to read the technical documentation very carefully, making a choice.
Such radiators in their reliability challenge the championship with cast iron, and in thermal return - with aluminum. The reason for this is their special design.
Each of the sections consists of two, upper and lower, steel horizontal collectors (pos. 1) connected by the same steel vertical channel (pos.2). The connection into a single battery is made by high-quality threaded couplings (pos. 3). High heat transfer is provided by an outer aluminum sheath.
Steel internal pipes Made from metal that are not subject to corrosion or has a protective polymer coating. well and aluminum heat exchanger Under no circumstances contact with the coolant, and corrosion is absolutely not terrible.
Thus, a combination of high strength and wear-resistant with excellent heat engineering indicators is obtained.
Radiators heating
Such batteries are not afraid of even very large pressure jumps, high temperatures. They are essentially universal, and suitable for any heating systems, however, the best performance features they are still shown in conditions high pressure central system - For contours with natural circulation, they are unsuitable.
Perhaps their only drawback is a high price compared to any other radiators.
For the convenience of perception, the table is posted in which comparative characteristics radiators. Legend in it:
| NG. | TC | Al. | AA | Bm | |
|---|---|---|---|---|---|
| Maximum pressure (atmospheres) | |||||
| working | 6-9 | 6-12 | 10-20 | 15-40 | 35 |
| pressing | 12-15 | 9 | 15-30 | 25-75 | 57 |
| destruction | 20-25 | 18-25 | 30-50 | 100 | 75 |
| PH restriction (hydrogen indicator) | 6,5-9 | 6,5-9 | 7-8 | 6,5-9 | 6,5-9 |
| Corrosion exposure under influence: | |||||
| oxygen | not | yes | not | not | yes |
| wandering currents | not | yes | yes | not | yes |
| electrolytic par | not | weak | yes | not | weak |
| Power of section at H \u003d 500 mm; DT \u003d 70 °, W | 160 | 85 | 175-200 | 216,3 | up to 200. |
| Warranty, years | 10 | 1 | 3-10 | 30 | 3-10 |
You may be interested in information about what is
It is clear that the radiator installed indoors (one or more) should ensure heating to a comfortable temperature and compensate for the inevitable heat loss, regardless of the weather on the street.
The basic value for calculations is always the area or the volume of the room. Value calculations themselves are very complex, and take into account a very large number of criteria. But for household needs, you can use simplified techniques.
It is believed that to create normal conditions in a standard residential room, a 100 W is enough per square meter of Plischy. Thus, you should only calculate the area of \u200b\u200bthe room and multiply it by 100.
Q. = S. × 100.
Q.- The required heat transfer from heating radiators.
S.- Square of the heated room.
If it is planned to install an unsubstantiated radiator, then this value will become a guide to select the desired model. In the case when batteries are installed, allowing the change in the number of sections, one more counts should be carried out:
N. = Q./ QU
N.- The calculated number of sections.
QU- Specific thermal power of one section. This value is mandatory indicated in the technical passport of the product.
As you can see, these calculations are extremely simple, and do not require any special knowledge of mathematics - enough roulette to measure the room and sheet of paper for computing. In addition, it is possible to use the table below - there are already calculated values \u200b\u200bfor rooms of various areas and certain capacities of heating sections.
Table Section
However, it must be remembered that these values \u200b\u200bare for the standard ceiling height (2.7 m) of the high-rise building. If the height of the room is different, then it is better to calculate the number of battery sections based on the volume of the room. This uses averaged indicator - 41 in t T.eplova power per 1 m³ volume in panel house, or 34 W - in the brick.
Q. = S. × h.× 40 (34)
where h.- the height of the ceiling above the floor level.
Further calculation is no different from the above.
And now we turn to more serious calculations. A simplified calculation method described above may present the hosts of the house or the surprise apartment. When the installed radiators are not created in the residential premises of the required comfortable microclimate. And the reason for this is a whole list of nuances, which the considered method simply does not take into account. Meanwhile, similar nuances may have very important.
So, the area of \u200b\u200bthe room is again taken again and all the same 100 W per m². But the formula itself is already somewhat different:
Q. = S. × 100 × a × in × s ×D.× E ×F.× G.× H.× I.× J.
Letters from BUT before J. Conditionally designated coefficients that take into account the features of the room and the installation of radiators in it. Consider them in the row:
A - number external walls in room.
It is clear that the higher the area of \u200b\u200bcontact of the room with the street, that is, the greater the room of the outer walls, the higher the general heat loss. This dependence takes into account the coefficient BUT:
B - orientation of the room on the sides of the world.
Maximum heat loss is always in rooms that direct sunlight does not come. This is definitely the northern side of the house, and this can also be attributed to the eastern - the rays of the sun here only in the morning when the shovel still "did not come to full power."
The southern and west sides of the house are always heated by the sun much stronger.
From here - the values \u200b\u200bof the coefficient IN :
C - coefficient, taking into account the degree of insulation of the walls.
It is clear that heat loss from heated premises will depend on the quality of thermal insulation of external walls. The value of the coefficient FROM Take equal:
D - Features of the climatic conditions of the region.
Naturally, it is impossible to equal all the basic indicators of the required heating capacity "under one comb" - they depend on the level of winter negative temperaturescharacteristic of concrete terrain. It takes into account the coefficient D.For its choice, the average temperatures of the cold decade of January are taken - usually this value is easy to clarify in the local hydrometeorological service.
E is the height of the ceiling ceilings.
As mentioned, 100 W / m² is averaged value for the standard height of the ceilings. If it differs, you should enter correction factor E.:
F- coefficient taking into account the type of room located above
To organize the heating system in rooms with cold floors - meaningless occupation, and the owners always take action on this issue. But the type of room, located above, often does not depend on them. Meanwhile, if there is a residential or insulated room from above, then the overall need for thermal energy will significantly decrease:
The accounting ratio of the type of installed windows.
Various window structures susceptible to heat loss unenkoso. It takes into account the coefficient G:
N is the coefficient of Plischi glazing space.
The total amount of heat loss depends on the total area of \u200b\u200bwindows installed indoors. This value is calculated on the basis of the relationship of the area of \u200b\u200bwindows to the area of \u200b\u200bthe room. Depending on the result obtained, we find the coefficient N.:
I- The coefficient taking into account the diagram of connecting radiators.
From how the radiators are connected to the pipes of the supply and returns, their heat transfer depends. This should also be taken into account when planning the installation and determining the desired number of sections:
J- coefficient, taking into account the degree of openness of the installed radiators.
Much depends on how much batteries are open for free heat exchange with air room. Available or artificially created obstacles are able to significantly reduce the heat transfer of the radiator. It takes into account the coefficient J:
a - Radiator is located open on the wall or not covered with a window sill - J \u003d 0.9
b - The radiator is covered on top of the windowsill or shelf - J \u003d 1.0
b - the radiator is covered on top of a horizontal protrusion of a wall niche - J \u003d 1.07
g - the radiator from above is covered with a window sill, and with frontal parties — partscNN covered with decorative casing - J \u003d 1,12.
d - the radiator is completely covered with decorative casing J \u003d 1,2
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Well, finally, that's all. Now it is possible to substitute the necessary values \u200b\u200bin the formula and the coefficients corresponding to the conditions, and the required thermal power is obtained at the output for reliable heating of the room, taking into account all the nuances.
After that, it will remain or select an unbearable radiator with the necessary thermal return, or divide the calculated value to the specific thermal power of one battery section of the selected model.
Surely, many such count will seem overly cumbersome, in which it is easy to get confused. To facilitate the calculations, we propose to use the special calculator - all the required values \u200b\u200bhave already been laid. The user remains only to enter the requested source values \u200b\u200bor select the desired positions from the lists. The "Calculate" button will immediately lead to an accurate result with rounding to the large side.
When upgrading the heating system, in addition to replacing pipes, radiators are changed. And today they are from different materials, different shapes and sizes. What is equally important, they have different heat transfer: the amount of heat that can transmit air. And it is necessarily taken into account when they make the settlement of radiators.
The room will be warm if the amount of heat that goes will be compensated. Therefore, in the calculations, they take the heat loss of premises (they depend on the climatic zone, from the material of walls, insulation, windows area, etc.). The second parameter is the thermal power of one section. This is the amount of heat that it can give at maximum system parameters (90 ° C at the inlet and 70 ° C at the output). This characteristic is necessarily indicated in the passport, it is often present on the package.
We make the calculation of the number of sections of heating radiators with their own hands, consider the features of the premises and the heating system
One important moment: Conducting calculations yourself, keep in mind that most manufacturers indicate the maximum figure that they received under ideal conditions. Because any rounding is made in the biggest. In case of low-temperature heating (The temperature of the coolant at the inlet below 85 ° C) is looking for thermal power for the respective parameters or recalculation (described below).
This is the simplest technique that allows you to roughly estimate the number of sections needed for the heating of the room. Based on many calculations, the norms on the average power of the heating of one square of the square are derived. To take into account the climatic features of the region, two standards were prescribed in SNE:
Why is such a big range in the standards? In order to take into account the materials of the walls and the degree of insulation. For houses from concrete, you take maximum values \u200b\u200bfor bricks, you can use average. For insulated houses - minimum. One more important detail: These norms are calculated for the middle ceiling height - no higher than 2.7 meters.
Knowing the area of \u200b\u200bthe room, multiply its heat cost rate that is most suitable for your conditions. Get a common heat loss room. In the technical data to the selected radiator model, find the thermal power of one section. Common heat loss divide into power, get their quantity. It is easy, but to be clearer, we give an example.
Corner room 16 m 2, in the middle lane, in brick house. Install the batteries with a thermal power of 140 W.
For brick house Take heat loss in the middle of the range. Since the room is angular, it is better to take more importance. Let it be 95 watts. Then it turns out that 16 m 2 * 95 W \u003d 1520 W is required for heating the room.
Now we consider the number of radiators for heating of this room: 1520 W / 140 W \u003d 10.86 pcs. Rounded, it turns out 11 pcs. So many sections of radiators will need to be installed.
The calculation of heating batteries to the square is simple, but not ideal: the height of the ceilings is not taken into account completely. With non-standard height, another technique is used: by volume.
There is in lowering the norm and for heating one cubic meter of premises. They are given for different types Buildings:
This calculation of the sections of radiators is similar to the previous one, only now it is not necessary for the square, and the volume and norm take others. The volume is multiplied by the rate obtained by the figure divide to the power of one section of the radiator (aluminum, bimetallic or cast-iron).
Formula for calculating the number of sections by volume
For example, we calculate how much sections in the room of 16 m 2 and the height of the ceiling is 3 meters. The building is built of brick. Radiators Take the same power: 140 W:
Now you know two ways to calculate the number of radiators on the room.
Today is a large range of radiators. With the external similarity of the majority, thermal indicators can differ significantly. They depend on the material from which are made, from the size, wall thicknesses, internal section and on how well the design is thought out.
Therefore, to say exactly how much kW in 1 sections of an aluminum (cast-iron bimetallic) radiator can only be said in relation to each model. This data indicates the manufacturer. After all, there is a significant difference in size: some of them are high and narrow, others are low and deep. The power of the section of one height of the same manufacturer, but different models, may differ by 15-25 W (see the table below STYLE 500 and STYLE PLUS 500). Even more tangible differences can be from different manufacturers.
However, to preliminarily evaluate how many battery sections are needed to heating the premises, the average thermal power values \u200b\u200bfor each type of radiators were removed. They can be used with approximate calculations (data for batteries with an inter-axis distance of 50 cm) are given:
More precisely, how much kW in one section of the radiator of bimetallic, aluminum or cast-iron you can, when select the model and decide on the dimensions. Very big can be the difference in cast iron batteries. They are with thin or thick walls, because of which their thermal power changes significantly. The above is the average values \u200b\u200bfor the batteries of the usual shape (harmonica) and close to it. Radiators in the style of "retro" thermal capacity is lower at times.
it specifications cast iron radios Turkish firm Demir Dokum. The difference is more than solid. She can be even more
Based on these values \u200b\u200band average standards in SNUP, the average number of radiator sections per 1 m 2 was derived:
These calculations are only approximate. You can roughly estimate the cost of acquiring heating devices. To accurately calculate the number of radiators on the room you can choose the model, and then by recounting the amount depending on which temperature of the coolant in your system.
We once again draw your attention to the fact that the thermal power of one battery section is indicated for ideal conditions. So much heat will give the battery if its coolant has a temperature of + 90 ° C at the inlet, at the output of + 70 ° C, it is maintained in the room + 20 ° C. That is, the temperature pressure of the system (called the "Delta system") will be 70 ° C. What if you do in your system above + 70 ° C at the entrance on it? Or is it necessary indoors + 23 ° C? Recalted the stated power.
To do this, it is necessary to calculate the temperature head of your heating system. For example, on your delivery + 70 ° C, at the output of + 60 ° C, and in the room you need a temperature of + 23 ° C. We find the delta of your system: this is the average arithmetic temperature at the inlet and outlet, minus the temperature indoors.
For our case, it turns out: (70 ° C + 60 ° C) / 2 - 23 ° C \u003d 42 ° C. Delta for such conditions 42 ° C. Next, we find this value in the recalculation table (located below) and the stated power multiply on this coefficient. We will teach the power that this section will be able to give for your conditions.
When recalculating in the following order. We find in columns squeezed in blue, a line with a 42 ° C. Delta. It corresponds to the coefficient of 0.51. Now we expect a thermal power of 1 radiator section for our case. For example, the declared power of 185 W, applied by the found coefficient, we obtain: 185 W * 0.51 \u003d 94.35 W. Almost two times less. Here is this power and you need to substitute when you make the calculation of the radiators sections. Only with the individual parameters in the room will be warm.
The calculation of radiators needs to be performed correctly, otherwise their small amount will not be able to warm up the room, and the largest, on the contrary, will create uncomfortable conditions of stay, and will have to constantly open the windows. Known miscellaneous techniques calculation. Their choice affects the material of batteries, climatic conditions, arrangement of the house.
16 x 100 \u003d 1600 W
Taken the most value of power consumed, since the weather is changed, and it is better to provide a small supply of power so that it is not freezing in winter.
1600 / 170 = 9,4
It is better to round up to the biggest - 10 pieces. But for some rooms it is advisable to round down in a smaller side, for example, for a kitchen, in which there are additional sources of heat. Then there will be 9 sections.
Calculations can be carried out according to another formula, which is similar to the above calculations:
N \u003d s / p * 100, where
In this case, the calculations based on the area of \u200b\u200bthe room are not suitable: it is necessary to apply the formula based on the volume of the room and make adjustment by applying the reducing coefficients or an increase in heat transfer.
The values \u200b\u200bof the coefficients are as follows:
P \u003d v x 41, where
If there is a room at 20 square meters. M (4x5 m - the length of the walls) with the height of the ceilings of 3 meters, then its volume is easy to calculate:
20 x 3 \u003d 60 W
The resulting value is multiplied by power adopted by norms:
60 x 41 \u003d 2460 W - so much heat is required to dig the area under consideration.
The calculation of the amount of radiators is reduced to the following (if we consider that one section of the radiator allocates 160 W allocates, and their exact data depend on the material from which the batteries are made):
2460/160 \u003d 15.4 pieces
We will take that you need only 16 sections, that is, you need to purchase 4 radiator for 4 sections per wall or 2 to 8 sections. It does not need to forget about the adjustment coefficients.
Some producers of radiators provide together with their product of the process of recalculating heat transfer and the coefficient. Her value is floating: the larger the temperature of the coolant, the greater the heat transfer rate.
(85 + 63) / 2 – 23 = 52
The obtained number is equal to DT, according to the proposed table, it can be established that with it the coefficient is 0.68. Given this, you can determine the heat transfer of one section:
199 x 0,68 \u003d 135 W
The calculation of the number of radiators is always relevant. Those who build a private houseThis is especially important. Owners of apartments who wanted to change the radiators should also know how to easily calculate the number of sections on new models of radiators.
On the issue of maintaining optimal temperature In the house, the main place is ranked radiator.
The choice simply amazes: bimetallic, aluminum, steel of various sizes.
There is nothing worse than the incorrectly calculated necessary thermal power in the room. In winter, such an error can be very expensive.
The thermal calculation of heating radiators is suitable for bimetallic, aluminum, steel and cast-iron radiators. Experts identify three methods, each of which is based on certain indicators.
There are three methods that are based on general principles:
Now let's turn directly to the methods themselves.
Based construction RulesFor high-quality heating of one square meter, 100 watts of the radiator power are required. We will be calculated.
Suppose the area of \u200b\u200bthe room is 30 m², the power of one section will take equal to 180 watts, then 30 * 100/180 \u003d 16.6. Rounded the value in the most side and we obtain that for a room of 30 square meters, 17 sections of the heating radiator are needed.
However, if the room is a corner, then the resulting value should be multiplied by a coefficient of 1.2. In this case, the number of necessary sections of radiators will be equal to 20
This method differs from the previous one that is based not only on the area of \u200b\u200bthe room, but also at its height. Please note that the method only works for medium and high power devices.
For low power (50 watts and less) Similar calculations will be ineffective in view of too much error.
So, if we take into account that the average height of the room is 2.5 meters (the standard height of the ceilings of most apartments), then one section of the standard radiator is able to heat the area of \u200b\u200b1.8 m².
The calculation of sections for the room in 30 "squares" will be as follows: 30/18 \u003d 16. Again, somewhat round and we get that it requires 17 radiator sections for heating this room.
As can be seen from the name, calculations in this method are based on the size of the room.
It is conditionally assumed that for heating 5 cubic meters of the room, 1 section of 200 watt is needed. With a length of 6 m, the width 5 and height of 2.5 m formula for the calculation will be as follows: (6 * 5 * 2.5) / 5 \u003d 15. Therefore, for the room with such parameters you need 15 sections of the heating radiator with a capacity of 200 watts each.
If the radiator is planned to be located in a deep open niche, then the number of sections should be increased by 5%.
In case the radiator is planned to be completely close, the increase should be made by 15%. Otherwise, it will be impossible to achieve optimal heat transfer.
The calculation of the number of sections of heating radiators is not the only way to properly organize the heating of the room.
Calculate the volume of the alleged room of 30 square meters. m and 2.5 m high:
30 x 2,5 \u003d 75 cubic meters.
Now you need to decide on the climate.
For the territory of the European part of Russia, as well as Belarus and Ukraine, the standard is 41 watts of thermal power into a cubic meter of the room.
To determine the required power, we multiply the size of the room on the standard:
75 x 41 \u003d 3075 W
Rounded the resulting value in the largest - 3100 W. For those people who live in conditions of very cold winters, this figure can be increased by 20%:
3100 x 1.2 \u003d 3720 W.
Having come to the store and clarify the power of the heating radiator, it is possible to calculate how many radiator sections will be required to maintain comfortable temperature even in the most severe winter.
The calculation method is an excerpt from the preceding paragraphs of the article.
After you calculate the required power to heat the room and the number of radiator sections, you come to the store.
If the number of sections came out impressive (it happens in premises with a large area), it will be reasonably not one, but several radiators.
This scheme is also applicable to those conditions when the power of one radiator is below the necessary.
But there is another fast way Calculate the number of radiators. If your room was old with a height of about 60 cm, and in winter you felt comfortable in this room, then consider the number of sections.
The resulting digit multiply 150 W is the necessary power of new radiators.
In the event of a choice or, you can buy them at the rate of 1 to 1- one edge of the cast-iron radiator 1 of the edge of bimetallic.
The division on the "warm" and "cold" apartment has long come to our lives.
Many people deliberately do not want to choose from and installing new radiators, explaining that "in this apartment will always be cold." But it is not.
The right choice of radiators in a literate calculation of the required power is able to make heat and comfort for your windows even in the coldest winter.
